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3 years ago

A pair of vertical angles has measures (2y+5)° and (4y)°.

Mathematics

1 answer:

kotegsom [21]3 years ago

7 0

(2y + 5)° = 4y °
- 4y + 2y° = -5°
-2y° = -5°
y =5/2

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ivann1987 [24]

Answer:

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Step-by-step explanation:

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3 years ago

How to check this answer 13=13+5(x-2)

USPshnik [31]

x=2

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13=13+5(x-2)

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3 years ago

Read 2 more answers

E^(8x)+e^(-x) find the interval on which f is increasing

saveliy_v [14]

Assuming ya mean
$f(x)=e^{8x}+e^{-x}$
take derivitive
remember dy/dx e^x=e^x
also the chain rule

so
$f'(x)=8e^{8x}+-1e^{-x}$
find where it equals 0
$0=8e^{8x}+-e^{-x}$
$e^{-x}=8e^{8x}$
multiply both sides by e^x
$1=8e^{9x}$
divide both sides by 8
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take ln of both sides
$ln(\frac{1}{8})=ln(e^{9x})$
$ln(\frac{1}{8})=9x$
divide both sides by 9
$\frac{ln(\frac{1}{8})}{9}=x$

x≈-1/5
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f'(0)>0

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3 years ago

NEED ASAP THANK YOU !!!!

alukav5142 [94]

Answer:

part a: -40 < x < 140

part b: open circles on both -40 and 140 with an arrow from each pointing inward. (towards zero). the solutions represent temperatures that will keep the gas in liquid form.

part c: it will freeze because -49 is less than -40, and therefore not a solution to the inequality.

explanation

a. x must be greater than -40 and less than 140 as outlined in the problem. so x > -40 and x < 140

b. open circles are non inclusive, and we do not include -40 or 140 because the gas will not be a liquid at those temps.

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umka2103 [35]

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3 years ago