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AnnZ [28]
3 years ago
11

Find the number C(10,6)

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

210.

Step-by-step explanation:

Combination formula is

nCr = \frac{n!}{r!(n-r)!}

Then, we have that n = 10 and r=6:

C(10,6) = \frac{10!}{6!(10-6)!}

C(10,6) = \frac{10!}{6!4!}

To simplify calculus, we are going to use that n! = (n-1)!n = (n-2)!(n-1)n and so on.

C(10,6) = \frac{6!*7*8*9*10}{6!4!}

C(10,6) = \frac{7*8*9*10}{4!}

C(10,6) = \frac{5040}{4*3*2*1}

C(10,6) = \frac{5040}{24}

C(10,6) = 210.

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4 years ago
A data set lists earthquake depths. The summary statistics are
irinina [24]

Answer:

Step-by-step explanation:

The summary of the given statistics data include:

sample size n = 400

sample mean \overline x = 6.86

standard deviation = 4.37

Level of significance ∝ = 0.01

Population Mean \mu = 6.00

Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

To start with the hypothesis;

The null and the alternative hypothesis can be computed as :

H_o: \mu = 6.00 \\ \\  H_1 : \mu \neq 6.00

The test statistics for this two tailed test can be computed as:

z= \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt {n}}}

z= \dfrac{6.86 - 6.00}{\dfrac{4.37}{\sqrt {400}}}

z= \dfrac{0.86}{\dfrac{4.37}{20}}

z = 3.936

degree of freedom = n - 1

degree of freedom = 400 - 1

degree of freedom = 399

At the level of significance ∝ = 0.01

P -value = 2 × (z < 3.936)  since it is a two tailed test

P -value = 2 × ( 1  - P(z ≤ 3.936)

P -value = 2 × ( 1  -0.9999)

P -value = 2 × ( 0.0001)

P -value =  0.0002

Since the P-value is less than level of significance , we reject H_o at level of significance 0.01

Conclusion: There is sufficient evidence to conclude that the original claim that the mean of the population of earthquake depths is  5.00 km.

7 0
3 years ago
Round each number to the nearest tenth. What is the best estimate for the answer to 841.37 + 24.13? A. 860 B. 865 C. 865.4 D. 86
Katyanochek1 [597]
D. 865.5 would be the nearest tenth
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3 years ago
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Of the 360 students at Moores school of Music, 270 are learning to play stringed instruments. What percent of the students are l
Sloan [31]

Answer:

75% of the students at the Moore school are are learning to play a stringed instrument.

Step-by-step explanation:

We are given the following in the question:

Total number of students at Moore school = 360

Number of students learning stringed instrument = 270

We have to find the percentage of the students who  are learning to play a stringed instrument.

Percentage =

=\dfrac{\text{Students are learning to play a stringed instrument}}{\text{Total number of students}}\times 100\5\\\\=\dfrac{270}{360}\times 100\%\\\\=75\%

Thus, 75% of the students at the Moore school are are learning to play a stringed instrument.

5 0
4 years ago
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