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Nikolay [14]
4 years ago
12

Do 8:14 and 20:35 form a proportion

Mathematics
2 answers:
IRISSAK [1]4 years ago
5 0

Answer:

8:14 could go to 4:7, and 20:35 can go to 4:7, so yes

Step-by-step explanation:


nadya68 [22]4 years ago
5 0
Yes, if you divide first one by 2 you get 4:7
Divide second one by 5 and you get 4:7
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What is the surface area of the square pyramid represented by the net? 9 m Enter your answer in the box 6 m 9m 6 m 9 m m 9 m​
Darya [45]

Answer:

144

Step-by-step explanation:

On this shape we are going to splt up the 4 triangles for the square to make it simple.

So, firstly, plug is the h an w of one of the triangles into the formula for the area of a triangle which is hxw/2

H=9

W=6

9x6/2=27

Then multiply the area of the triangle, 27, to get the total area of all 4 triangles (since they all have the same measurements)

27x4=108

108 is the area of all 4 triangles

Next, just put the l and w into the equation for the area of a square which is lxw

L=6

W=6

6x6=36

36 is the area of the square

Lastly, just add the areas of the triangles and the square together

108+36=144

144 is the total area/surface area, of the pyramid

5 0
2 years ago
Which expression is equivalent to 15 - 5x? select all that apply
m_a_m_a [10]
Choices A and B are correct. To find the equivalent expressions, you would do the distributive property for the choices to
get rid of the parentheses. You would then see which choices match up with 15 - 5x. Hope this helps!
A.) -5x + 15 (yes)
B.) 15 - 5x (yes)
C.) -15 + 5x (no)
D.) 5 - x (no)
3 0
3 years ago
A person is standing close to the edge on a 56 foot building and throws the ball vertically upward. The quadratic function h(t)=
Romashka [77]

Answer:

Part 1)

225 feet.

Part 2)

7 seconds.

Step-by-step explanation:

The height h(t) of the ball above the ground after <em>t</em> seconds is modeled by the function:

h(t)=-16t^2+104t+56

Part 1)

We want to determine the maximum height of the ball.

Notice that the function is a quadratic with a negative leading coefficient, so its maximum will be at its vertex point.

The vertex of a parabola is given by:

\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a</em> = -16, <em>b</em> = 104, and <em>c</em> = 56.

Find the <em>x-</em> (or rather <em>t-</em>)<em> </em>coordinate of the vertex. So:

\displaystyle t=-\frac{(104)}{2(-16)}=\frac{104}{32}=\frac{13}{4}=3.25\text{ seconds}

In other words, the ball reaches its maximum height after 3.25 seconds.

To find the maximum height, substitute this value back into the function. Hence:

\displaystyle h(3.25)=-16(3.25)^2+104(3.25)+56=225\text{ feet}

The maximum height of the ball is 225 feet in the air.

Part 2)

We want to find the amount of time it took for the ball to hit the ground.

When the ball hit the ground, its height above the ground is zero. Therefore, we can set h(t) to 0 and solve for <em>t: </em>

0=-16t^2+104t+56

We can simplify a bit. Divide both sides by -8:

0=2t^2-13t-7

We can factor. Find two numbers that multiply to 2(-7) = -14 and add to -13.

-14 and 1 works! Therefore, split the second term into -14 and 1:

\displaystyle 0=2t^2-14t+t-7

Factor out a 2<em>t</em> from the first two terms and group the last two terms:

0=2t(t-7)+(t-7)

Factor by grouping:

0=(2t+1)(t-7)

Zero Product Property:

2t+1=0\text{ or } t-7=0

Solve for each case:

\displaystyle t=-0.5\text{ or } t=7

Since time cannot be negative, we can ignore the first case.

Therefore, it takes seven seconds for the ball to hit the ground.

6 0
3 years ago
Write the point-slope form of the equation of the line passing through the points (-5, 6) and (0, 1).
ludmilkaskok [199]
Slope of the line
(6-1) / (-5-0)
5 / -5
-1

General equation of the line
y = -x + c
if this passes through (0,1)
0 = (-1*1) + c
c = 1

so the equation is
y = -x + 1
5 0
3 years ago
How many tens, hundreds, thousandten thousands are listed in the numbers below.
nordsb [41]


#1. 50 tens or 5 hundreds

#2. 110 tens, 11 hundreds, or 1 thousand 1 hundred

#3. 300 tens, 30 hundreds, or 3 thousands.

#4. 2500 tens, 250 hundreds, 25 thousands, or 2 ten thousands 2 thousands

#5. 6000 tens, 600 hundreds, 60 thousand, or 6 ten thousands.

#6. 11000 tens, 1100 hundreds, 110 thousands, or 11 ten thousands.

#7. 2500 tens, 250 hundreds, 25 thousands, or 2 ten thousands 5 thousands

#8.90000 tens, 9000 hundreds, 900 thousands, or 90 ten thousands

8 0
3 years ago
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