Step-by-step explanation:
initial speed = 272 ft/s
h = -16t² + 272t
a. 1120 = -16t² + 272t we change a bit into
16t² - 272t + 1120 = 0 then divide all with factor 16
t² - 17t + 70 = 0
(t - 10)(t - 7) = 0
t = 10 and t = 7
7 s when it goes up and 10 sec when the rocket goes down.
b. 1152 = -16t² + 272t we change a bit into
16t² - 272t + 1152 = 0 then divide all with factor 16
t² - 17t + 72 = 0
(t - 9)(t - 8) = 0
t = 9 and t = 8 sec
c. since the answer of a and b is:
7 sec and 8 sec the rocket goes up but at 9 sec and 10 sec the rocket goes down then we can take conclusion that the maximum height is reached at 8.5 s
so how long the rocket in the air?
goes up : 8.5 sec
goes down : 8.5 sec
total = 17 sec
Answer:
113.04 sq. in.
Step-by-step explanation:
If the diameter of the circle is 12", then the radius is 6" (half the diameter), and the area "A" is (approximately) 3.14 * 6^2. The calculation is approximate because 3.14 is a rounded value for pi.
Answer:
30
Step-by-step explanation:
Substitue 3 for every x in the equation
10(3)-(3*3)(2*3)+(3)^2(2*3)
Multiply
30-(9)(6)+9(6)
30-54+54=30
The scale factor for the first one is 2.25
And for the second one it’s 7
I hope this helps :)
Answer:
math a app good luck with the question
