Ask question

Ask question

All categories

3 years ago

13

Mrs. Marks has 3/4 pounds of cheese to use making sandwiches. She use about 1/32 pounds of cheese on each sandwich can she make

with the cheese she has?

1 answer:

Nostrana [21]3 years ago

4 0

Answer: 24

Step-by-step explanation: she can make 24 sandwiches because 1/32 times 24 = 3/4

hope this helps

You might be interested in

Find the least common multiple of 4,10,12

nata0808 [166]

The LCM of 4,10 and 12 is 60.

7 0

3 years ago

Read 2 more answers

The regular price of a pair of sneakers is $65. They are on sale for 20% off. What is the sale price?

Fofino [41]

65*0.20=13 (0.20 because 20/100=20% is 0.20 in decimal form)
65-13=52

4 0

3 years ago

Read 2 more answers

Which function transforms the graph of y=x^2 so that it is first shifted up 3 units and is then reflected across the x-axis?

AveGali [126]

Can someone help me on this question?

7 0

3 years ago

Read 2 more answers

Find the surface area of the pyramid shown to the nearest whole number. The base is a regular hexagon.

Fiesta28 [93]

The surface area of the pyramid will be given as follows:
Area of triangles:
A=1/2×base×height
A=1/2×12×18
A=108 m²
Area of 6 triangles is given by:
A=108×6=648 m²

Area of the hexagon:
A=6×1/2×12×6√3
A=374.123m²

Total surface area:
SA=648+374.123
SA=1022.123 m²~1022 m²

Answer: C] 1022 m²

8 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago