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Vilka [71]
3 years ago
11

HALP MEH PLS

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0

1,3

1,1

0,0

This should be the correct answer

Stella [2.4K]3 years ago
3 0

Answer:

L' = (0,-2)

K' = (3,-2)

J' = (3,0)

Step-by-step explanation:

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Needing answers, giving brainliest.
Semmy [17]

Answer:

1 13/28

Step-by-step explanation:

3×4/28 + 5×4/28. it 28 because the lcm of 4 and 7 is 28

21/28+20/28=41/28=1 13/28

8 0
2 years ago
−39 = −0.6k<br> what does k equal
denis-greek [22]

Answer: k=65

Step-by-step explanation:

4 0
3 years ago
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Find x.<br> x = 4<br> x = 5<br> x = 6
ivann1987 [24]
X=5, should be right correct me if i’m wrong.
7 0
3 years ago
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If the measure of angle 1 is 110 degrees and the measure of angle 3 is (2 x + 10) degrees, what is the value of x?
user100 [1]

Answer:

Correct option is

B

90

∘

,90

∘

,90

∘

Let AB and CD be two lines Intersecting at O, such that, ∠AOD=90

∘

Now, ∠AOD=∠COB=90

∘

(Vertically opposite angles)

⟹∠AOD+∠DOB=180

o

(Angles on a straight line)

⟹90+∠DOB=180

o

∠DOB=90

∘

∠DOB=∠AOC=90

∘

(Vertically opposite angles)

Thus, all angles are 90

∘

.

7 0
2 years ago
In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
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