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DaniilM [7]
3 years ago
9

Solve for n (look at attachment)

Mathematics
1 answer:
Virty [35]3 years ago
3 0
First distribute 6 into the parenthesis so that would be (6n - 18) - 2n = 10. Then erase the parenthesis to make the subtraction easier. So that would be 6n-18-2n=10. Then solve the subtraction by separating the unknown numbers with n and the normal numbers. So 6n-2n=4n 4n-18=10. To find n, add 18 and 10 to make both sides of the equation equal. So that would make 4n=28. Therefore n would be 7 because 28 divided by 4 makes 7.
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Solve the system of equations by using the inverse of the coefficient matrix of the equivalent matrix equation.
Alinara [238K]

The solution for the given system of equations x + 8y = -37, 4x + 8y = -52 is \left[\begin{array}{ccc}&5&\\\\&4&\end{array}\right]

Given,

System of equations as,

x + 8y = -37

4x + 8y = -52

We have to solve this by using the inverse of coefficient matrix of the equivalent matrix equation.

That is,

A=\left[\begin{array}{ccc}a&&b\\\\c&&d\end{array}\right]

A^{-1} =\frac{1}{ad -bc} \left[\begin{array}{ccc}d&&-b\\\\-c&&a\end{array}\right]

Now we can solve the equations.

Here we have,

x + 8y = -37

4x + 8y = -52

Now in matrix form,

\left[\begin{array}{ccc}1&&8\\\\4&&8\end{array}\right]  \left[\begin{array}{ccc}&x&\\\\&y&\end{array}\right] =\left[\begin{array}{ccc}&-37&\\\\&-52&\end{array}\right]

      A               X                  B

We know that,

A^{-1} =\frac{1}{ad -bc} \left[\begin{array}{ccc}d&&-b\\\\-c&&a\end{array}\right]

Therefore,

A^{-1} = \frac{1}{(1X8)-(4X8)} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]

       =\frac{1}{8-32} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]

       =\frac{1}{-24} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]

       =\left[\begin{array}{ccc}\frac{-8}{24} &&\frac{8}{24} \\\\\frac{4}{24} &&\frac{-1}{24} \end{array}\right]

Then,

\left[\begin{array}{ccc}&x&\\\\&y&\end{array}\right] ==\left[\begin{array}{ccc}\frac{-8}{24} &&\frac{8}{24} \\\\\frac{4}{24} &&\frac{-1}{24} \end{array}\right]  \left[\begin{array}{ccc}&\frac{37}{52} &\\\\\end{array}\right]

                =\frac{1}{24} \left[\begin{array}{ccc}-8&&8\\\\4&&-1\end{array}\right]\left[\begin{array}{ccc}&\frac{37}{52} &\\\\\end{array}\right]

                =\frac{1}{24} \left[\begin{array}{ccc}(-8X37)+(8X52)\\\\(4X37)+(-1X52)\end{array}\right]

               =\frac{1}{24} \left[\begin{array}{ccc}-296+416\\\\148-52\end{array}\right]

               =\frac{1}{24} \left[\begin{array}{ccc}120\\\\96\end{array}\right]

               =\left[\begin{array}{ccc}\frac{120}{24} \\\\\frac{96}{24} \end{array}\right]

              =\left[\begin{array}{ccc}5\\\\4\end{array}\right]

That is \left[\begin{array}{ccc}x\\\\y\end{array}\right] =\left[\begin{array}{ccc}5\\\\4\end{array}\right]

Learn more about matrix equations here: brainly.com/question/27799804

#SPJ4

The question is incomplete. Completed question is given below:

Solve The System Of Equations By Using The Inverse Of The Coefficient Matrix Of The Equivalent Matrix Equation.

x + 8y = -37

4x + 8y = -52

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In KLM, LM=7 and angle K=45. Find KL. Leave your answer in simplest radical form.
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Answer in simplest radical form would be 7.(:
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Tonya has $2000 in savings. She wants to save more money. She is considering two options:
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I think the answer is A have a good day buddy
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What is the second step when you construct a copy of a line segment
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Answer: The second step for copying a line segment is to set the compass to the length of the line segment to be copied.

When copying a line segment, you must first create your starting point.

Then, you need to set your compass to the length of the line segment to be copied. 

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The standard deviation is the average distance of each score in a distribution from the
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The answer is the mean. In statistics, the standard deviation is a measure that is used to compute the amount of variation or distribution of a set of data values. In other words, standard deviation (also variance) are measures of the spread of the data around the mean. They summarize how near each observed data value is to the mean value. A low standard deviation indicates that the data points tend to be close to the mean (otherwise known as the expected value) of the set, while a high standard deviation indicates that the data points are vast over a wider range of values.
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