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Monica [59]
3 years ago
9

3 Sarah left home at 10:00 and cycled north in

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

a) From 10 to 11, Sarah rode 12 km in one hour. That means her velocity was 12 km/hr.

b) Sarah passed by her home at 12:45.

c) From 12 to 13, Sarah rode 15 km. Thus, her velocity was 15 km/hr. From 13 to 14 she rode 3 km. Thus, her velocity was 3 km/hr.

d) Her average velocity was 12+0+15+3/4, or 30/4 which is 7.5 km/hr.

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<span>If the company, hewerrtt, would like to make letter codes using all of the letters in the word hewerrtt, they would be able to make five codes. Altogether, there are eight letters in the word, but there are duplicates of the letter e, the letter r, and the letter t, so that takes out three possibilities. Three subtracted from eight is equal to five, therefore the company can make five codes using the company name.</span>
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PLEASE helppp. What equation describes a line that is perpendicular y=-2/7x+5 and has the same y-intercept as y = 3x - 2?
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y = 7/2 -2

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if the slope of the first problem is -2/7 then its perpendicular is 7/2 (the exact opposite) and since the y- intercept is the b in Y= mx +b the intercept of the equation you’re trying to find is -2

6 0
3 years ago
Suppose a scientist reported the following data regarding the presence bacteria during the first four hours of testing for a new
OlgaM077 [116]

The recursive geometric sequence that models this situation is:

f(n) = 0.9f(n-1)

f(1) = 90000

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

It can be represented by a recursive sequence as follows:

f(n) = qf(n-1)

With f(1) as the first term.

In this problem, the sequence is: 90.000: 81,000; 72,900; 65,610, hence:

q = \frac{65610}{72900} = \cdots = \frac{81000}{90000} = 0.9

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More can be learned about geometric sequences at brainly.com/question/11847927

7 0
2 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is  an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

   ?          = 2000ft3

              = 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

4 0
3 years ago
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