Step-by-step explanation:
there are different ways you could do it using the elimination and substitution method.
hope this helps you!
-s.
<h3>For the lowest common multiple you do your times tables.</h3><h3>For example,5,10,15,20,25,30,35,40,45,50.</h3><h3>Those are your times tables of 5.</h3><h3>On the other side do your 6 times tables up to 60.</h3><h3>6,12,18,24,30,36,42,48,54,60.</h3><h3>Now that you have got both,Write down the smallest number in them that they both have.</h3><h3>For example,it would be<u> 30.</u></h3>
This is because that’s the smallest number in the multiple of both numbers.
x=3
\fhjsihfuioshifhdniasi uikfsd gf vndghdf
(-2, -1) so y = <span>-2(-2) + 3 = 7; FALSE
</span>(3, 3) so y = -2(3) + 3 = -3; FALSE<span>
(3, -3) </span>so y = -2(3) + 3 = -3; TRUE<span>
(-3, -9) </span>so y = -2(-3) + 3 = 9; FALSE
answer
<span>(3, -3)</span>
