The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.
<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>
The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.
i.e.
By factorization, we have:
Now, to get exactly 30 divisor.
- (p+2)² requires to give us 15 factors.
Therefore, we can have an equation p + 2 = p₁ × p₂²
where:
- p₁ and p₂ relate to different values of odd prime numbers.
So, for the least values of p + 2, Let us assume that:
p + 2 = 5 × 3²
p + 2 = 5 × 9
p + 2 = 45
p = 45 - 2
p = 43
Therefore, we can conclude that the smallest prime number p such that
p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.
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Answer:
2 1/3
Step-by-step explanation:
You take the first number them multiply then divide
Answer:
See explanation
Step-by-step explanation:
1. R is the set of all integers with absolute value less than 10, thus
2. A is its subset containing all natural numbers less than 10, thus
3. B is the set of all integer solutions of inequality 2x+5<9 that are less than 10 by absolute value (and therefore, it is also a subset of R). First, solve the inequality:
Thus,
See the diagram in attached diagram.
Note that
Answer:
l am sorry l do not get the question
Answer:
Step-by-step explanation:
Formula for straight lines:
where m = slope, b = constant
Given:
y-intercept = -3 (0, -3)
m = ⅛
Substitute into formula to find b.
Substitute b into original formula
