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3 years ago

What is (19-1) X (7-6)

Mathematics

1 answer:

kkurt [141]3 years ago

4 0

19 - 1 = 18 and 7 - 6 = 1

Since anything multiplied by 1 is itself, the answer is 18.

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How do you solve 30 and 31

Westkost [7]

Answer:

(#30) 1.12 miles

Step-by-step explanation:

9.7x.75=7.27

r=7.27

8.2x.75=6.15

e=6.15

7.27-6.15=1.12

1.12 miles

8 0

3 years ago

What is the LCM of 6, 10, and 15?<br> 50

Thepotemich [5.8K]

Answer:

okay

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

the line of symmetry of a parabola whose equation is y = ax ^ 2 - 4x + 3 is =-2 what is the value of "a"

77julia77 [94]

Y= ax² -4x +3

-b/2a is x - coordinate of the vertex,
line of symmetry x=-2, x=-2 is a coordinate of the vertex also, because the line symmetry has vertex.

x= -b/2a
x= -2, b= -4
-2=-(-4)/2a
-2=4/2a
-2=2/a
a=2/(-2)=-1
a= - 1

5 0

3 years ago

54 is greater than 45

Alinara [238K]

Yes 54 is greater then 45!

3 0

3 years ago

Read 2 more answers

Insert geometric means in each geometric sequence.

Digiron [165]

Answer:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the $n^{th}$ term of a geometric sequence.

$a_n=ar^{n-1}$

Where $a$ is the first term and

$r$ is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

$ar = 24\\ar^4 = \dfrac{3}{64}$

Solving the above equation:

$r = \dfrac{1}{8}$

Therefore, the sequence is:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

Considering the second given sequence:

$ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2$

Therefore, the sequence is:

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

Considering the third sequence:

$a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3$

Therefore, the sequence is:

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

5 0

3 years ago