Answer:
29.4 meters
Step-by-step explanation:
Given the following :
A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
distance it moved between two positions. Use the "distance on the number line "formula
Initial Position or distance of submarine before ascension = 56.8 meters
Final position after ascension = 27.4 meters
The distance moved by the submarine between the two positions can be obtained by.
(Initial distance - Final distance)
(56.8 - 27.4) = 29.4 meters
[1]
A1 = (h (a + b)) / 2
A1 = (21 (17 + 32)) / 2
A1 = (21 x 49) / 2
A1 = 1,029 / 2
A1 = 514.5 mm²
[2]
A2 = (b x h) / 2
A2 = (11 x 9) / 2
A2 = 99 / 2
A2 = 49.5 mm²
[3]
The area of the shaded region =
A1 - A2 =
514.5 mm² - 49.5 mm² =
465 mm²
The answer is 465 mm².
The answer has to be 1,350 is that one of your options
Answer:
1137
Step-by-step explanation:
5675+453
6128
Now
7265-6128
1137
Answer:
55 is 11% of 500.
You invested 500$
Step-by-step explanation: