hydrogen and oxygen I believe
Answer:
1. a) 0,18
2. e) The reaction proceeds to the left, forming more BrCl(g).
Explanation:
1. In a gas reaction as:
2SO₂(g) +O₂(g) ⇄ 2SO₃(g)
it is possible to convert kp to kc using:
kp = kc (RT)^Δn
Where kp is gas equilibrium constant, kc is equilibrium constant (13), R is gas constant (0,082atmL/molK), T is temperature (900K), and Δn is number of moles of gas products - number of moles of gas reactants (That is 2 - (2+1) = -1). Replacing:
kp = 13×(0,082atmL/molK×900K)^-1
<em>kp = 0,18</em>
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2. Based on Le Chatelier's principle, the change in temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system. For the reaction:
2 BrCl(g) ⇄ Br₂(g) + Cl₂(g).
The addition of 0,050M of each compound cause <em>the reaction proceeds to the left, forming more BrCl(g)</em> because based on the reaction, you need two moles of BrCl per mole of Br₂(g) and Cl₂(g) to keep the system in the same. But you are adding the same proportion of moles of each compound.
I hope it helps!
Answer:
the potential with respect to a silver–silver chloride electrode is 0.715
Explanation:
the potential to a silver chloride electrode can be derived from the question above by saying that
the potential with respect to a silver–silver chloride electrode? = 0.9120v - 0.197 V
= 0.715
therefore, the potential with respect to a silver–silver chloride electrode is 0.715
Answer:
true
Explanation:
pigment contains chlorine which gives color
