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3 years ago

In an experiment, what variable does the experimenter observe as a result of the

Chemistry

1 answer:

Sonja [21]3 years ago

3 0

A. only volume (cm³) is the independent variable

B. both volume (cm³) and mass (grams) are independent variable

C. not enough information

D. the slope of the trend line

E. only mass (grams) is the independent variable

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Lithium diisopropylamide [(CH3)2CH]2NLi, referred to as LDA, enjoys many uses as a strong base in synthetic organic chemistry. I

meriva

Answer:

Lithium diisopropylamide [(CH3)2CH]2NLi.

Explanation:

Lithium diisopropylamide (commonly abbreviated LDA) is a chemical compound with the molecular formula [(CH3)2CH]2NLi. It is used as a strong base and has been widely accepted due to its good solubility in non-polar organic solvents and non-nucleophilic nature. It is a colorless solid, but is usually generated and observed only in solution. It was first prepared by Hamell and Levine in 1950 along with several other hindered lithium diorganylamides to effect the deprotonation of esters at the α position without attack of the carbonyl group.

5 0

3 years ago

The Mond process produces pure nickel metal via the thermal decomposition of nickel tetracarbonyl: Ni(CO)4 (l) → Ni (s) + 4CO (g

Yuki888 [10]

Answer: The volume of CO formed is 254.43 L.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $Ni(CO)_4$ = 444 g

Molar mass of $Ni(CO)_4$ = 170.73 g/mol

Putting values in above equation, we get:

$\text{Moles of }Ni(CO)_4=\frac{444g}{170.73g/mol}=2.60mol$

For the given chemical reaction:

$Ni(CO)_4(l)\rightarrow Ni(s)+4CO(g)$

By stoichiometry of the reaction:

1 mole of nickel tetracarbonyl produces 4 moles of carbon monoxide.

So, 2.60 moles of nickel tetracarbonyl will produce = $\frac{4}{1}\times 2.60=10.4mol$ of carbon monoxide.

Now, to calculate the volume of the gas, we use ideal gas equation, which is:

PV = nRT

where,

P = Pressure of the gas = 752 torr

V = Volume of the gas = ? L

n = Number of moles of gas = 10.4 mol

R = Gas constant = $62.364\text{ L Torr }mol^{-1}K^{-1}$

T = Temperature of the gas = $22^oC=(273+22)K=295K$

Putting values in above equation, we get:

$752torr\times V=10.4mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 295K\\\\V=254.43L$

Hence, the volume of CO formed is 254.43 L.

5 0

4 years ago

What is the oxidation state of S in so ??

Marina86 [1]

Answer:

Explanation:

If a compound $SO$ existed, we would identify the oxidation state of sulfur using the following logic:

oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
oxygen typically has an oxidation state of -2;
we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
write the equation for the net charge of 0 by adding all individual charges of the two atoms: $x + (-2) = 0$ ;
hence, x = 2.