The answer is D) 1/2.
Let's imagine that two genes of the genotype can be analysed separately.
Black fur is determined by dominant allele B. In this case, parents Bb and BB will give offspring with only brown fur:
Parents: Bb x BB
Offspring: BB BB Bb Bb
Both homozygous (BB) and heterozygous (Bb) offspring will have black fur.
On the other hand, long tails are determined by recessive allele t. Parents Tt and tt will have 50% offspring with short tail and 50% offspring with long tail:
Parents: Tt x tt
Offspring: Tt Tt tt tt
Heterozygous offspring (Tt) will have short tail, and homozygous offspring (tt) will have a long tail.
So, the offspring will definitely have black fur and will not affect the fraction of the offspring with black fur and long tails from the cross of <span>BbTt × BBtt. But, </span>there will be 2 out of 4 offspring with short tails which is 50% or 1/2.
Answer and Explanation:
<u>Cruza</u>: persona sana sin mutaciones con persona portadora
El parental sano aporta alelos normales del gen a la descendencia
El parental portador aporta un alelo normal y un alelo alterado. Tiene el 50% de probabilidad de transmitir la enfermedad a la progenie.
Parental) AA x Aa
Gametas) A A A a
Cuadro de Punnet) A A
A AA AA
a Aa Aa
F1) 2/4 = 1/2 = 50% de la progenie seran individuos sanos AA
2/4 = 1/2 = 50% de la progenie seran individuos portadores Aa
Como uno de los progenitores es portador, cada individuo tiene un 50% de posibilidades heredar el gen alterado.
It started in 1798, to the 1800. This period is when the human population began to grow at a faster rate then any other time in history.
>Got my answer right on gradpoint<
The answer is 300 years ago.
The answer choices were.
A 300 years ago
B 8,000 years ago
C 20,000 years ago
D 1,000 years ago
