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rusak2 [61]
3 years ago
14

Find the size of the final unknown exterior angle in a polygon whose

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

72

Step-by-step explanation:

The sum of exterior angles is 360

360-57-68-32-59-72 =. 72

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Enter a formula in cell B3 using the Vlookup function to find the meaning for thr medical abbrevation listed in cell A3. use the
NeX [460]
Formulas tab > in the Function Library group, click Lookup & Reference button, select VLOOKUP. Type A3 in the Lookup_value argument box. Type Abbreviation in the Table_array argument box. Type 2 in the Col_num argument box. Type False in the Rang_lookup box. Click OK, is this what you were looking for?
8 0
2 years ago
A rock is thrown from the top of a tall building.The distance in feet between the rock and the ground t seconds after thrown is
marusya05 [52]

Answer:

0.448 seconds

Step-by-step explanation:

d = -16t² -4t + 412

find t when d = 407

substituting d = 407 into the equation:

407 = -16t² -4t + 412 (subtract 407 from both sides)

-16t² -4t + 412 - 407 = 0

-16t² -4t + 5 = 0 (multiply both sides by -1)

16t² + 4t - 5 = 0  

solving using your method of choice (i.e completing the square or using the quadratic equation), you will end up with

t = (-1/8) (1 + √21)= -0.70 seconds (not possible because time cannot be negative)

or

t = (-1/8) (1 -√21) = 0.448 seconds (answer)

4 0
3 years ago
Find the slope of the line through the points (−3, 6) and (2, 6).
Elden [556K]

Answer:

There wouldn't be a slope. It would be 0/5

Step-by-step explanation:

\frac{6-6}{2+3}

6 - 6 = 0

2 + 3 = 5

0/5 isn't a slope.

7 0
3 years ago
Read 2 more answers
Help please and simplify answer in radical form if needed
deff fn [24]

Answer:

16\sqrt{3}\:\mathrm{units^2}

Step-by-step explanation:

The area of an equilateral triangle with side length s is equal to \frac{\sqrt{3}}{4}s^2. Since the perimeter is 24 units and there are three equal sides to an equilateral triangle, each side is 24\div 3=8 units.

Substituting in this value, we get:

\frac{\sqrt{3}}{4}8^2=\frac{64\sqrt{3}}{4}=\boxed{16\sqrt{3}}

6 0
3 years ago
Please help me with this question fast.
Sergeeva-Olga [200]
C since the value of the original changed by moving 2 units to the left, thus x-2 and y+5 since it moved 5 up
4 0
2 years ago
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