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Mademuasel [1]
3 years ago
12

Sove -5x + 3 = 2x - 1

Mathematics
2 answers:
DiKsa [7]3 years ago
7 0

Answer:

4/7

Step-by-step explanation:

zubka84 [21]3 years ago
6 0

Answer:

x = 4/7

Step-by-step explanation:

-5x + 3 = 2x - 1

         -3          -3

-5x = 2x - ( -4)

-(-2x) - (-2x)

- 7x = -4

——-  ——

 7      7

x = 4/7

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oksian1 [2.3K]

Answer:

yes

Step-by-step explanation:

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3 years ago
I need help with this ASAP! (Click on the image I uploaded)
3241004551 [841]

Answer:

<em>d</em> = 24.63

Step-by-step explanation:

82.53 - (21.7 + 17.3 + 18.9) =

24.63

4 0
3 years ago
Use differentials to estimate the amount of paint needed to apply a coat of paint 0.07 cm thick to a hemispherical dome with dia
Mademuasel [1]

An hemispherical dome is half a sphere. If the diameter is 60 m, then the radius is 30 m.

We can use differentials to solve this problem because we are adding a thin layer to the original dome, so the volume of the dome in increased by a differential of itself.

This differential volume that the dome is increased is equal to the volume of the coat of paint.

The volume of the dome can be written as:

\begin{gathered} V=\frac{4\pi}{3}r^3 \\ \frac{dV}{dr}=\frac{4\pi}{3}\cdot3r^2\Rightarrow dV=\frac{4\pi}{3}\cdot3r^2\cdot dr=4\pi r^2\cdot dr \end{gathered}

Now, we can calculate dV as:

\begin{gathered} dV=4\pi r^2\cdot dr \\ dV\approx4\cdot3.14\cdot(30m)^2\cdot0.07\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}} \\ dV\approx12.57\cdot900m^2\cdot0.0007m \\ dV\approx7.92m^3 \end{gathered}

Answer: the paint needed for this coat is approximately 7.92 m^3

5 0
1 year ago
If (inserted image), then f(2)=<br> A)1/3<br> B)1<br> C)7
Lubov Fominskaja [6]

Given : f(x) = 3x + 1

We get f(2) by substituting x = 2 in the given Function

⇒ f(2) = 3(2) + 1

⇒ f(2) = 6 + 1 = 7

Option C is the Answer

6 0
3 years ago
ASAP Please answer fast!!!!!!
leonid [27]

The difference between relation and function is described

<em><u>Solution:</u></em>

Let us first understand about relation and function

A relation is a set of inputs and outputs that are related in some way.

When each input in a relation has exactly one output, the relation is said to be a function.

To determine if a relation is a function, we make sure that no input has more than one output

Every function is a relation ,but every relation doesn't represent a function

<em><u>Example:</u></em>

R = {(2, x), (9, y), (2, z)}  

It is not function as “2” is input for both x and z

F = {(2, x), (9, y), (5, x)} is a function because all the first elements are different.

<em><u>Differences:</u></em>

<em><u>Relation:</u></em>

  • A relation is a relationship between sets of values
  • A relation is denoted by “R”
  • Every relation is not a function.

<em><u>Functions:</u></em>

  • A function is a relation in which there is only one output for each input.
  • A function is denoted by “F” or “f”
  • Every function is a relation.
7 0
3 years ago
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