The earth travels one full rotation around the sun in approximately365.25 days.
Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:

Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:

c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:

d) The expected flight time is E(t)=122.5

Answer:
(3 x + 2) (5 x - 4)
Step-by-step explanation:
Factor the following:
15 x^2 - 2 x - 8
Factor the quadratic 15 x^2 - 2 x - 8. The coefficient of x^2 is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12. So 15 x^2 - 2 x - 8 = 15 x^2 - 12 x + 10 x - 8 = 5 x (3 x + 2) - 4 (3 x + 2):
5 x (3 x + 2) - 4 (3 x + 2)
Factor 3 x + 2 from 5 x (3 x + 2) - 4 (3 x + 2):
Answer: (3 x + 2) (5 x - 4)
I’m not exactly sure but I think it is G