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garri49 [273]
4 years ago
13

Jeremy rides a Ferris wheel. The graph shows h, Jeremy’s height above the ground at any time during the ride. Which inequality r

epresents the heights shown on the graph? 10 < h < 50 10 ≤ h ≤ 50 h > 10 or h < 50 h ≥ 10 or h ≤ 50

Mathematics
2 answers:
geniusboy [140]4 years ago
4 0

Answer:

10 \leq h\leq 50

Step-by-step explanation:

Jeremy rides a Ferris wheel. The graph shows h, Jeremy’s height above the ground at any time during the ride

Number line represents the height above the ground at any time during the ride.

the shaded part of the graph lies between 10 and 50, also we have solid dot at 10 and 50.

So height of the inequality is

10 \leq h\leq 50

fredd [130]4 years ago
4 0

Answer:

b. 10 ≤ h ≤ 50

Step-by-step explanation: just took the test

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A wave has a wavelength of 25 cm. It passes a particular point for five seconds. 35 crests pass the point during the five second
Kazeer [188]
80 cycles per second
6 0
3 years ago
Find the solution set for 8x - 3 = 2(x - 1/2)​
KiRa [710]

Answer:

x = 1/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

8x - 3 = 2(x - 1/2)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distributive 2:                              8x - 3 = 2x - 1
  2. Subtract 2x on both sides:         6x - 3 = -1
  3. Add 3 to both sides:                   6x = 2
  4. Divide 6 on both sides:              x = 1/3
4 0
3 years ago
21. Find x, given AD = BC =6 m.​
BigorU [14]

Answer:

Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.

Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.

Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.

Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!

6 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that n = 292, \pi = \frac{52}{292} = 0.178

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

3 0
3 years ago
Please can you help me. Thanks.
Katena32 [7]

Answer:

1

Step-by-step explanation:

The average rate of change is measured as

\frac{f(b)-f(a)}{b-a} in the closed interval [ a, b ]

here [ a, b ] = [ - 5, 5 ]

f(b) = f(5) = - 5² + 5 + 3 = - 25 + 8 = - 17

f(a) = f(- 5) = -(- 5)² - 5 + 3 = - 25 - 2 = - 27

Hence

average rate of change = \frac{-17-(-27)}{5-(-5)} = \frac{10}{10} = 1


4 0
3 years ago
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