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Pepsi [2]
4 years ago
5

What does 3x + 8y + 13x equal???

Mathematics
1 answer:
Zigmanuir [339]4 years ago
7 0
Simplifying 3x + 8y + 13x = 0
<span>Reorder the terms: 3x + 13x + 8y = 0
</span><span>Combine like terms: 3x + 13x = 16x 16x + 8y = 0
</span>Solving 16x + 8y = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8y' to each side of the equation. 16x + 8y + -8y = 0 + -8y <span>Combine like terms: 8y + -8y = 0 16x + 0 = 0 + -8y 16x = 0 + -8y Remove the zero: 16x = -8y
</span>Divide each side by '16'. x = -0.5y
<span>Simplifying x = -0.5y</span>







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Akira and Hideo are twins with different jobs. Akira earns five-eighths of what Hideo earns, but Akira’s expenses are half of Hi
aleksklad [387]

9514 1404 393

Answer:

  25%

Step-by-step explanation:

Apparently, we're to assume that anything not spent is saved.

Let Hideo's income be 1. Then Akira's income is 5/8. Akira's expenses are 60% = 3/5 of that value, so ...

  Akira's expenses = (3/5)(5/8) = 3/8  . . . . . of Hideo's income

Hideo's expenses are twice this amount, so ...

  Hideo's expenses = (2)(3/8) = 3/4 . . . . . of Hideo's income

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3 years ago
Fishing Hook G is let down 2 times its present depth. Where is Fishing Hook G?
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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

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4 years ago
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Step-by-step explanation:

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