I think it’s 6
I did 32-26 and got it
That’s all I got
The time taken for the particle to travel more than 8 meters from the point of projection is 0.59 s.
<h3>
Time of motion of the particle</h3>
The time taken for the particle to travel more than 8 meters from the point of projection is calculated as follows;
s = v₀t + ¹/₂at²
8 = 12t + (0.5 x 5)t²
8 = 12t + 2.5t²
2.5t² + 12t - 8 = 0
solve the equation using formula method
t = 0.59 s
Thus, the time taken for the particle to travel more than 8 meters from the point of projection is 0.59 s.
Learn more about time of motion here: brainly.com/question/2364404
Answer:
Step-by-step explanation:
B
its B
we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.
![\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20%5Cmeasuredangle%20SQR%20%3D%20%5Cmeasuredangle%201%20%2B%20%5Cmeasuredangle%202%5C%5C%5C%5C%20%5Cmeasuredangle%202%20%3D%20%5Cmeasuredangle%201%20%3D%205x-7%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Cmeasuredangle%20SQR%7D%7B7x%2B13%7D%20%3D%20%28%5Cstackrel%7B%5Cmeasuredangle%201%7D%7B5x-7%7D%29%2B%28%5Cstackrel%7B%5Cmeasuredangle%202%7D%7B5x-7%7D%29%20%5C%5C%5C%5C%5C%5C%207x%2B13%20%3D%2010x-14%5Cimplies%2013%3D3x-14%5Cimplies%2027%3D3x%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B27%7D%7B3%7D%3Dx%5Cimplies%209%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cmeasuredangle%20SQR%20%3D%207%289%29%2B13%5Cimplies%20%5Cmeasuredangle%20SQR%20%3D%2076)
The values of x are -22 and -2 and there are not extraneous solutions
<h3>How to solve the equation?</h3>
The equation is given as:
2|x + 7|= x - 8
Expand the absolute bracket
|2x + 14|= x - 8
Remove the absolute bracket
2x + 14 = x - 8 and 2x + 14 = -x + 8
Evaluate the like terms
x = -22 and 3x = -6
This gives
x = -22 and x = -2
Hence, the values of x are -22 and -2 and there are not extraneous solutions
Read more about absolute value expressions at:
brainly.com/question/24368848
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