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3 years ago

The distance between the points (-3,0) and (4,0) is

Mathematics

2 answers:

hram777 [196]3 years ago

5 0

Answer:

$\sqrt{7}$

Step-by-step explanation:

$\sqrt{(4 - ( - 3) + (0 - 0)}$

$\sqrt{(4 + 3) + 0}$

$\sqrt{7 + 0}$

$\sqrt{7}$

Phantasy [73]3 years ago

5 0

Answer:

Step-by-step explanation:

Two points P1 (x1,y1) and P2(x2,y2)

d=SQRT((x2-x1)^2+(y2-y1)^2))

choose your points

let (-3,0) be (x1,y1)

let (4,0) be (x2,y2)

Substitute the values into the equation

SQRT((4-(-3))^2+(0-0)^2))

Simplify

SQRT(7^2+0)

Square root of 7 squared is 7 or -7, however distance cannot be negative so the answer is 7

This applies to all two points however there is a faster solution for these two points as they have the same y value meaning you could've just drawn a line between these two points on a Cartesian plane and counted 7.

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3 years ago

What is 6 7/9 as an improper fraction? Explain your answer.

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Answer:

Step-by-step explanation:

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3 years ago

Solve the “and” compound inequality for –1 < 6x + 1 ≤ 13

ser-zykov [4K]

Answer:

-1/3 < x <(or equal to) 2

Step-by-step explanation:

Firstly divide your inequality into two separate inequalities...

1) -1 < 6x + 1...then solve for the first one..,which then gives you....;

-2 < 6x....which gives us our first solution (x > -1/3)

Then the second inequality

2) 6x + 1 <(or equal to) 13

which then gives you....,

6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)

Then combine the two solutions into a compound solution

-1/3 < x <(or equal to) 2

8 0

3 years ago

A rectangle has an area of 21x + 81 square units. If the width is 3 units, what is the length of the rectangle

rosijanka [135]

If x=3 then the answer is 144

6 0

3 years ago

Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in

Alborosie

Answer:

a) Null hypothesis: $p\geq 0.53$

Alternative hypothesis: $p < 0.53$

b) $z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429$

$p_v =P(Z$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

$\hat p=0.46$ estimated proportion of American families owning stocks or stock funds

$p_o=0.53$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:

Null hypothesis: $p\geq 0.53$

Alternative hypothesis: $p < 0.53$

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .

7 0

3 years ago