18. s = 5r^2 + 7......making r the subject
s - 7 = 5r^2
(s - 7) / 5 = r^2...by taking the sqrt of both sides, it eliminates the ^2
( sqrt (s-7)/5) = r
19. h = ut - 1/2gt^2....u = 100, t = 1 4/5(or 9/5)...g = 6.4
h = (100)(9/5) - 1/2(6.4)(9/5^2)
h = 180 - 1/2(6.4)(3.24)
h = 180 - 3.2(3.24)
h = 180 - 10.368
h = 169.632 or 169 79/125
20. sorry..do not know this one
8 can go into 270 evenly.....90 times to be exact so the answer is 90
Answer : Probability that the pumping system will fail on any given day = 0.005
Explanation:
Probability that only older pump fail = P(A) = 0.10
Probability that only newer pump fail = P(B) = 0.05
Since they are independent events ,
then the conditions will be
P(A∩B) = P(A). P(B)
= 0.10 ×0.05
= 0.005
Hence, the probability will fail on any given day = 0.005
Answer:
Step-by-step explanation:
The solution is in the attached file
