F(x) = x 3 − 1000x^2 + x − 1
> x3 − 1000x^ 2
= (x − 1000)x^2
> (.9x)x^2
= .9x^3
Therefore, f(x) is Ω(x^3 ) with C = .9, k = 10, 000. Also, for all x > 0:
f(x) = x^3 − 1000x^2 + x − 1
< x^3 + 1000x^3 + x^3 + x^3
= 1002x^3
Therefore, f(x) is O(x^3 ) with C = 1002, k = 1.
(8,9)
To find the midpoint of coordinates is adding all the X axis coordinates and dividing it by 2 (9+7 divided by 2=8)
Same goes for the Y axis (5+13 divided by 2= 9)
Answer:
The equation that represents the motion of the string is given by:
.....[1] where t represents the time in second.
Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.
Substitute the given values in [1] we get;
or
(a)
The trigonometric function that models the motion of the string is given by:
![y =0.6e^{-1.8t}\cos(210\pi t)](https://tex.z-dn.net/?f=y%20%3D0.6e%5E%7B-1.8t%7D%5Ccos%28210%5Cpi%20t%29)
(b)
Determine the amount of time t that it takes the string to be damped so that ![-0.24\leq y \leq0.24](https://tex.z-dn.net/?f=-0.24%5Cleq%20y%20%5Cleq0.24)
Using graphing calculator for the equation
let x = t (time in sec)
Graph as shown below in the attachment:
we get:
the amount of time t that it takes the string to be damped so that
is, 0.5 sec
since the 2 lines are running horizontal and vertical angle 1 is a 90 degree angle
so 90 = 4y-2
92 = 4y
y = 23
Answer:
d = 7h +5
Step-by-step explanation
If you go to K-12 then this is the right answer I just took the quiz.