Answer:
I.
A is a 4 x 5 matrix => A: U -> V, dim U = 5, dim V = 4
Null space is exactly two dimensional plane
dim null (A) = 2
II.
Rank A = dim U - dim Null A = 5 - 2 = 3
III.
Number of linearly Independent columns of A is the rank of A = 3
IV.
Yes, The system Ax = b has no solution sometimes as range of A \neq V
V.
Yes,Sometimes Ax = b has a unique solution
VI.
Yes, sometimes Ax = b has infinitely many solutions
Answer:
12 minutes
Step-by-step explanation:



So, he spent 12 minutes jogging.
You can take in x values starting from -4 to 4. Substitute the x values in the equation and find the y values.
Using the values, you can plot the line.
Easy :)
36=2*2*3*3=2²*3²
60=2*2*3*5=2²*3*5
LCM(36,60)=2*2*3*3*5=2²*3²*5=180
3x + 7 = x
First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like:

= x
Fourth, simplify

to

/ Your problem should look like:

= x
Fifth, switch sides. / Your problem should look like: x =

Answer as fraction:

Answer as decimal: -3.5