I think the answer would have to be D. If the diameter, which is the distance from one point on the circle through the center to another point on the circle, is halved then the amount of concrete that will be needed will be multiplied by 4. I think that's right I am so sorry in advance if that was incorrect. Have a beautiful rest of your day. Stay safe. C O V I D - 1 9 IS REAL THIS COULD MEAN YOUR LIFE!!!
Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
Answer:
Jamie's claims are correct because 3/10 of the spool twine is left over after using 1/2 of the spool twin for friendship knot
Step-by-step explanation:
Full question: He claims to have 3/10 of the original spool of twine leftover.
First, we compare 3/10 with 4/5 - 1/2
The lowest common multiple for2 and 5 is 10.
To write 4/5 as a fraction with common denominator, multiply numerator and denominator by 2
4/5 = (4×2)/(5×2) = 8/10
To write 1/2 as a fraction with a common denominator, multiply denominator and numerator by5
1/2 =(1×5)/(2×5) = 5/0
So we have :
8/10 - 5/10
Since denominators are equal ,we go ahead and subtract
8/10 - 5/10 = (8-5)/10 = 3/10
27) if a = 1/a
multiply both sides by a
a * a = 1/a * a
a^ 2 = 1
Answer is D) 1
28)
6 x 75 = 450
7 x 80 = 560
8 x 85 = 680
9 x 90 = 810
Total all students in class = 6 + 7 + 8 + 9 = 30 students
Total score of whole class:
450 + 560 + 680 + 810 = 2500
Average = 2500 /30 = 83.3 = 83 1/3
Answer is C) 83 1/3
The answer is C) glide and reflection because if it were graphed, it would be reflected a line equal to x and slid, or glided upward. Hope this helps! :D
