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AnnZ [28]
3 years ago
9

At your school, the building is 20 feet tall, a tree's height is 252 inches, and the flagpole is 6 yards high. Which of the thre

e objects casts the longest shadow?
Mathematics
1 answer:
timurjin [86]3 years ago
3 0
First, all the heights have to be converted to similar units, say feet.

Therefore,
Building= 20 feet
Tree = 252*0.083333 = 21 feet
Flagpole = 6*3 = 18 feet

The tallest of the three is the tree and thus should cast the longest shadow. However, it should be noted that at exactly noon when the sun is overhead, all the three will have equal length of shadow (that is, 0 feet long).
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Answer:

2

Step-by-step explanation:

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Charles has $54.50 saved. He will save $33.25 each week for 30 weeks. How much money will Charles have after 30 weeks?
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Water level in a well was 20m below ground level. During rainy season, rainwater collected in different water tanks was drained
IgorC [24]

Answer:

17 m

Step-by-step explanation:

As shown in the figure,  A_0-B_0 is the ground level, A_1-B_1 is the old level of water which was at 20 m below ground level, A_2-B_2 is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.

The minimum length of the rope is equal to the distance between the pully and the new water level, indicated by the length L_0 in the figure.

So, L_0= 20-5+1.20+0.80= 17m

Hence, Raghu must use a rope having the minimum length 17 m to draw water from the well.

6 0
3 years ago
In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five tre
yawa3891 [41]

Answer:

MSE = 10

Step-by-step explanation:

Given

SSTR = 200

SST = 800

Required

Determine MSE

This is calculated as:

MSE = \frac{1}{ddf} * SSE

Where:

SSE = SST - SSTR

ddf \to denominator df

So, we have:

SSE = 800 - 200

SSE = 600

To calculate the df, we have:

r = 13 --- observations

n = 5 treatments

So:

ddf = Total\ df - Numerator\ df

Total = n*r-1 = 5*13 -1 = 64

Numerator =n - 1 = 5 - 1 =4

ddf =64-4=60

So, we have:

MSE = \frac{1}{ddf} * SSE

MSE = \frac{1}{60} * 600

MSE = 10

6 0
2 years ago
Given f(x) = 3x^3+ kx – 11, and x – 1 is a factor of f(x), then what is the value<br> of k?
STatiana [176]

let's recall the remainder theorem.

we know that (x-1) is a factor, that means x -1 = 0 or x = 1.

since we know that (x-1) is a factor, then dividing the polynomial by it will give us a remainder of 0, which correlates with saying that f(1) = 0, in this case, so we can simply plug in "1" as the argument, knowing it gives 0.

f(x)=3x^3+kx-11\\\\[-0.35em]~\dotfill\\\\\stackrel{0}{f(1)}=3(1)^3+k(1)-11\implies \stackrel{f(1)}{0}=3+k-11\implies 0=-8+k\implies 8=k

7 0
2 years ago
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