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4 years ago

Suppose there is a 3.1 temperature drop for every thousand feet that an airplane climbs

Mathematics

1 answer:

SSSSS [86.1K]4 years ago

6 0

Answer:

34.1 degrees

Step-by-step explanation:

given that the temperature drops 3.1 degrees for every thousand feet of elevation.

for an altitude of 11,000 feet (i.e 11 x 1000 feet), the temperature (compared to ground level) would drop,

= 3.1 deg / 1000-foot x 11,000 feet

= 34.1 degrees

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Draw a graph that illustrates the given situation: You ride your bike to your friend's house. You leave your house, which is at

Marianna [84]

Answer:

Please find attached the required drawing that illustrates the given situation

Step-by-step explanation:

With a driving speed of 0.003 miles per second, which is approximately 4.83 meters per second, we have the drawing of the graph that represent the given situation which is create with Microsoft Excel and attached alongside here

The total time for the travel is approximately 2,244 second with a total distance of approximately 6.732 miles, using angles, 60° for a steep slope and 30° for a gentle slope

3 0

3 years ago

Lines a and b are perpendicular. The equation of line a is =13+3 y = 1 3 x + 3 . What is the equation of line b ?

maksim [4K]

Answer:

See below

Step-by-step explanation:

Perpendicular lines have slopes which are negative reciprocals. Line a with the equation y = 13x + 3 has slope 13. This means Line b which is perpendicular will have slope -1/13.

The equation of line b is any equation where -1/13 is the slope/

Example: y = -1/13x + 5 or y = -1/13x - 6

6 0

3 years ago

Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries

kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

$\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04$

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535
$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465$

64.65% probability of at least one injury commuting to work in the next 20 years

3 0

3 years ago

Mike went on a vacation to ohio.When he went home the odemeter read 7,219.4 miles.When he returned home the odemeter read 8,192.

a_sh-v [17]

Answer:

973.2 miles

Step-by-step explanation:

miles travelled = miles on the odemeter after the trip - miles on the odemeter before the trip

8192.6 - 7219.4 = 973.2

3 0

3 years ago

Jim Lee received his bank statement from Bayne Bank indicating a balance of $7,980. Lee's checkbook showed a balance of $6,800.

bezimeni [28]

Given:
Bayne Bank indicating a balance of $7,980.
Lee's checkbook showed a balance of $6,800.
checks outstanding were $1,330.
NSF check for $120 and a service charge of $30.

Bank balance: 7,980
less: outstanding checks (1,330)
Bank balance, end 6,650

Jim's checkbook balance: 6,800
less: NSF check 120
service charge 30 (150)
Jim's balance, end 6,650

The reconciled balance is: $6,650.

In reconciling the bank balance, we need to add the deposits in transit and deduct the outstanding checks. This are all transactions reflected in the book but not yet reflected in the bank account.

In reconciling the book balance, we need to add the credits made in the bank account and deduct the debits like service charges.

5 0

3 years ago