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sineoko [7]
3 years ago
7

The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

The choices are: A. 6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8 B. 6d5 – 4c3d2 + 3c2d3 – 4cd4 + 8 C. 6d5 – 4c3d2 + 5c2d3 – 12cd4 + 8 D. 6d5 – 2c3d2 – 3c2d3 – 4cd4 + 8
Mathematics
2 answers:
Anit [1.1K]3 years ago
5 0

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8

Hence, the correct option is A.

ValentinkaMS [17]3 years ago
3 0

Answer:

6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8

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49x^2=-21x-2 quadratic functions
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Step-by-step explanation:

Quadratic function:

In elementary algebra, the quadratic formula is a formula that provides the solution to a quadratic equation. There are other ways of solving a quadratic equation instead of using the quadratic formula, such as factoring, completing the square, graphing and others.

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Use the quadratic formula



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Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.Separate

x=(-21+7) /98

x=(-21-7) /98

Solve

Rearrange and isolate the variable to find each solution

x=-1/7

x=-2/7



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