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3 years ago

10

I need help on algebra

2 answers:

boyakko [2]3 years ago

5 0

Just remember the syllables PEMDAS which stand for Parentheses, Exponents, Multiplication, Division, Addition and Subtraction. If you can’t remember it, just write it on the side of your paper. But make sure to use it in that order.

ki77a [65]3 years ago

3 0

Answer:

1) 5x³ + 3x²

2) 25 - 3x⁵

3) -4ab + 2a² + 26

4) p²q³ + pq

Step-by-step explanation:

Like terms are expressions like 3x and 2x or 5x² and 8x².

1) x² + 5x³ + 2x²

5x³ + 3x²

2) -2x⁴ + 16 + 2x⁴ + 9 - 3x⁵

-2x⁴ + 2x⁴ + 25 - 3x⁵

25 - 3x⁵

3) ab - a² + 4² - 5ab + 3a² + 10

ab - a² + 16 - 5ab + 3a² + 10

ab - a² - 5ab + 3a² + 26

ab - 5ab + 2a² + 26

-4ab + 2a² + 26

4) 3p²q² - 3p²q³ + 4p²q³ - 3p²q² + pq

3p²q² + p²q³ - 3p²q² + pq

p²q³ + pq

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4 years ago

Solve both equations.

lakkis [162]

Equation 1:

Answer:

x = 1.22

Step-by-step explanation:

$\frac{5x-1}{8} -\frac{5-7x}{2} = \frac{3(6-x)}{6}$

$\frac{2(5x-1) - 8(5-7x)}{16} = \frac{3(6-x)}{6}$

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Equation 2:

Answer:

x = -13.97

Step-by-step explanation:

$\frac{x}{3} - \frac{7(x-2)}{9} = 4- \frac{2x-5}{6}$

$\frac{9x-3(7(x-2))}{27} = 4- \frac{2x-5}{6}$

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$\frac{9x-(21x-42)}{27} = \frac{24 - (2x-5)}{6}$

$\frac{-12x+42}{27} = \frac{-2x+29}{6}$

$(-12x+42) \times 6 = (-2x+29) \times 27$

$(-72x+252) = (-34x+783)$

$(252-783) = (-34x +72x)$

$(-531) = (38x)$

$x =\frac {-531}{38}$

x = -13.97

5 0

3 years ago

Given h(t)= -2(t+5)^2+4, find h(-8)<br> –334<br> –14<br> 45<br> 445

Stells [14]

$h(t)=-2(t+5)^2+4$
$h(-8)=-2(-8+5)^2+4=-2(-3)^2+4=-2\cdot 9+4=-18+4=-14$
Answer B. -14

8 0

4 years ago

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