An actual two-by-two table is a tabular representation containing two rows and two columns.
- The columns consist of the tested True positive for prostate cancer and tested True Negative for prostate cancer
- The rows consist of the predicted positive screening and predicted negative values
<h3>a)</h3>
Mathematically, the set-up of the two-by-two table for this data can be computed as:
Tested True Positive for cancer True Negative Total
Predicted Positive 800 3200 4000
Predicted Negative 100 95900 96000
Total 900 99100 100000
<h3>b)</h3>
The prevalence rate of prostate cancer in this population is:


= 9 per thousand.
<h3>
c)</h3>
The calculation of the sensitivity of this screening is as follows:

where;
- TP = True positive for cancer
- PN₁ = Predicted Negative for true positive cancer
∴

= 0.889
= 88.9%
The interpretation shows that 88.9% are correctly identified to be actual positive for prostate cancer.
<h3>d)</h3>
The calculation of the specificity of this screening is as follows:

where;
- TN = True positive for cancer
- PN₂ = Predicted Negative for true negative cancer
∴

= 0.9677
= 96.77%
The interpretation shows that 96.7% of an actual negative is correctly identified as such.
<h3>
e)</h3>
The positive predicted value of the screening test is computed as:


= 0.2
= 20%
The interpretation of the positive predicted value of this screening shows that 20% that are subjected to the diagnosis of positive prostate cancer truly have the disease.
Learn more about tabular representation here:
brainly.com/question/8307968
Answer:
36
Step-by-step explanation:
you have to do ratios like
3=3 6=6 for sodas
and hotdogs
2=5 4=10 6=15 8=20 10=25 12 =30
hope this helps
-mercury
Is there more to the question? I’m confused on the content. Maybe a chart you forgot to post or something
Answer:
Area of a trapezium = 1/2(a+b)×h
where a and b are parallel sides of the trapezium
h is the height
First question
We must first find the height of the trapezium using Pythagoras theorem
That's
h² = 8² -3²
h =√ 64 - 9
h = √ 55m
a = 7m
b = 10+3 = 13m
Area of the trapezoid = 1/2(7+13)×√55
= 1/2×20×√55
= 74.16
= 74m² to the nearest tenth
Second question
We use sine to find the height
sin30° = h/12
h = 12 sin 30°
h = 6 in
Let the other half of the parallel side be x
To find the other half of the parallel side we use Pythagoras theorem
That's
x² = 12²- 6²
x = √144-36
x = √108
x = 6√3 in
So for this trapezoid
a = 9 in
b = (9 + 6√3) in
h = 6 in
Area of the trapezoid = 1/2(9 + 9+6√3) × 6
= 1/2(18+6√3)×6
= 85.176 in²
= 85 in² to the nearest tenth
Hope this helps you
Answer:
A 6.4
Step-by-step explanation:
(4/5)/(1/8) this is the answer