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kotykmax [81]
3 years ago
11

Joseph built a model of a pyramid where the base of the pyramid is a square. if the base has an area of 49 cm, what is the side

length of the base?
solution
how do you know
Mathematics
1 answer:
Tema [17]3 years ago
8 0
7, as the square root of 49 is 7

(The sides would be equal, and so the area would be one side squared)
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Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

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The coordinates of the fourth vertex is D(4,-3)

8 0
3 years ago
What is the percent equation for 46% of 127?
Brut [27]

Answer:

46% of 127 is 58.42

Step-by-step explanation:

46/100 = x/127

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The way I figured this one out was saying that if it takes 2lbs to stretch it to 12 inches and 5lbs to stretch to 18 inches that means that 3 additional pounds = 6 inches. Therefore, each additional pound is 2 inches. We know already that with 2 lbs it was 12 inches in length and we can also say that 2 lbs = 4 inches. So subtract 4 from 12 and you end up with the answer of 8 inches. 
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Natasha2012 [34]

Answer:

C = (\frac{21}{5},\frac{33}{5})

Step-by-step explanation:

Given

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Required

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Represent the ratio as ratio

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The new coordinate can be calculated using

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C = (\frac{21}{5},\frac{33}{5})

Hence;

<em>The coordinates of the new center is </em>C = (\frac{21}{5},\frac{33}{5})<em></em>

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Step-by-step explanation:

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