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2 years ago

12

Divide using long division.

^{2} -5x+3)" alt="(4x^{2} -5x+3)" align="absmiddle" class="latex-formula"> ÷ $(x+3)$

2 answers:

frez [133]2 years ago

6 0

Answer:

The quotient = 4x - 17 and the remainder = 54

Step-by-step explanation:

$\frac{4x^{2}-5x+3 }{x+3}=4x+\frac{-17x+3}{x+3}$

$\frac{-17x+3}{x+3}=-17+\frac{54}{x+3}$

The quotient = 4x - 17 and the remainder = 54

lara [203]2 years ago

4 0

Answer:

See attachment

Step-by-step explanation:

The given expression is $(4x^2-5x+3)\div (x+3)$

We perform the long division as shown in the attachment.

The quotient is $4x-17$ .

The remainder is $54$

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