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irga5000 [103]
3 years ago
9

Suppose that F(x)=x^3 and G(x)=-5x^3. Which statement best compares the graph of G(x) with the graph of F(x)?

Mathematics
2 answers:
aev [14]3 years ago
7 0

Answer:

Multiplying the x^3 term by 4 means you're stretching it vertically, adding the minus sign means you're flipping it about the x-axis, and subtracting 5 means you're moving it down by 5 units.

Step-by-step explanation:


Vlad1618 [11]3 years ago
6 0

Answer: The graph of G(x) is the graph of F(x) stretched vertically, flipped over the x-axis, and shifted 2 units up


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4688-3) -30X-5 CX-5)
pshichka [43]

Answer:

x = 13/3

Step-by-step explanation:

4(8x-3) - 30x = 5(x-5)

Distribute

32x - 12 - 30x  = 5x -25

Combine like terms

2x -12 = 5x-25

Subtract 2x from each side

2x-12-2x = 5x-2x -25

-12 = 3x-25

Add 25 to each side

-12+25 = 3x-25+25

13 = 3x

Divide each side by 3

13/3 = x

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4 years ago
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Help with two step equations with fractions.........<br> 2/3x=6
pashok25 [27]
Multiply 2/3 by the reciprocal, 3/2, on both sides.
3 0
3 years ago
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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
Helppppp pls im stuck on thi one problem :(
Ray Of Light [21]

First, find the simplified ratio of the given ratio:

Number of pirates: 22

Number of ships: 2

Divide 22 with 2 to find the ratio: 22/2 = 11

For every ship there is, there will be 11 pirates.

Now, find the ratio for the other questions:

IF there are 5 ships: 5 x 11 = 55

If there are 5 ships, there will be 55 pirates.

If there are 11 ships: 11 x 11 = 121

If there are 11 ships, there will be 121 pirates.

~

5 0
3 years ago
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PLEASE HELP!! WILL MARK BRAINLIEST!!!
Licemer1 [7]

Answer:

Look Down

Step-by-step explanation:

1) x=9

2) x=12

3) x=12

4) x=12

5) x=11

6) x=11

4 0
3 years ago
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