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irga5000 [103]
3 years ago
9

Suppose that F(x)=x^3 and G(x)=-5x^3. Which statement best compares the graph of G(x) with the graph of F(x)?

Mathematics
2 answers:
aev [14]3 years ago
7 0

Answer:

Multiplying the x^3 term by 4 means you're stretching it vertically, adding the minus sign means you're flipping it about the x-axis, and subtracting 5 means you're moving it down by 5 units.

Step-by-step explanation:


Vlad1618 [11]3 years ago
6 0

Answer: The graph of G(x) is the graph of F(x) stretched vertically, flipped over the x-axis, and shifted 2 units up


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Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar. How much soy sauce doe
natali 33 [55]

First step

You must stablish a relation  

150 ml sauce/100 ml vinegar

If   100 ml vinegar_______150ml sauce  then  11 ml vinegar ____x ml sauce

Second step

You must resolve x from the equation  

X= (11ml vinegar*150 ml soya)/(100 ml vinegar)= 16.5 ml sauce, it means that it will be  16,5 ml sauce by every 11 ml  of vinegar


5 0
3 years ago
Read 2 more answers
A map scale shows a scale of 1 inch = 50 miles. How many miles are represented by 4.5 inches on the map?
a_sh-v [17]

Answer:

Step-by-step explanation:

take 50*4.5 and you'll get your answer

7 0
2 years ago
What is the greatest common factor of 20x6y+40x4y2−10x5y5 ?
mestny [16]
The greatest common factor: 20x^6y 40x^4y^2 10x^5y^5 is 10x^4y.
20x^6y = 10x^4y*2x^2
40x^4y^2 = 10x^4y*4y
10x^5y^5 = 10x^4y*y^4


8 0
3 years ago
Which functions can generate all the values in table 2​
Whitepunk [10]

Answer:

animania-1.12.2-1.6.2.jar

4 0
2 years ago
Help!! Find missing value for each quadratic function
Svetllana [295]

I'll do the first one to get you started. The answer is -3

=================================================

Explanation:

When x = -1, y = 0 as shown in the first column. The second column says that (x,y) = (0,1) and the third column says (x,y) = (1,0)

We'll use these three points to determine the quadratic function that goes through them all.

The general template we'll use is y = ax^2 + bx + c

------------

Plug in (x,y) = (0,1). Simplify

y = ax^2 + bx + c

1 = a*0^2 + b*0 + c

1 = 0a + 0b + c

1 = c

c = 1

------------

Plug in (x,y) = (-1,0) and c = 1

y = ax^2 + bx + c

0 = a*(-1)^2 + b(-1) + 1

0 = 1a - 1b + 1

a-b+1 = 0

a-b = -1

a = b-1

------------

Plug in (x,y) = (1,0), c = 1, and a = b-1

y = ax^2 + bx + c

0 = a(1)^2 + b(1) + 1 ... replace x with 1, y with 0, c with 1

0 = a + b + 1

0 = b-1 + b + 1 ... replace 'a' with b-1

0 = 2b

2b = 0

b = 0/2

b = 0

------------

If b = 0, then 'a' is...

a = b-1

a = 0-1

a = -1

------------

In summary so far, we found: a = -1, b = 0, c = 1

Therefore, y = ax^2 + bx + c turns into y = -1x^2 + 0x + 1 which simplifies to y = -x^2 + 1

------------

The last thing to do is plug x = 2 into this equation and simplify

y = -x^2 + 1

y = -2^2 + 1

y = -4 + 1

y = -3


3 0
3 years ago
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