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snow_tiger [21]
4 years ago
9

Write the y-intercept of x=5y-10

Mathematics
1 answer:
oksano4ka [1.4K]4 years ago
5 0
The y-intercept can be found by plugging in x=0. x = 5y-10\\0=5y-10\\5y=10\\y=2\\\\\boxed{\sf{y-intercept: (0,2)}}
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A store wants to print flyers to a advertise its grand opening.A printer will charge $50 and 0.05 per flyer.If the store has a b
Kamila [148]

So it can be

x=number of flyers

50+0.05x=100

0.05x=50

x=1000 flyers


Hope this helps

7 0
3 years ago
DESCRIBE HOW TO WRITE 3 DIGIT NUMBERS IN THREE DIFFERENT WAYS
victus00 [196]
Just put each number in different positions.
425
542
254
All of these numbers are different and use the same 3 digits
3 0
3 years ago
Complete the explanation of the procedure that can be used to solve 5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55. Then solve the e
Debora [2.8K]

Answer:

x =  2.

Step-by-step explanation:

5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55

5[3x + 12 - 2 + 2x] - x - 15 = 14x + 55

5[5x + 10] - x - 15 = 14x + 55

25x + 50  - x - 15 = 14x + 55     Now we subtract 14x from both sides:

25x + 50  - x - 15  - 14x = 14x - 14x + 55

10x + 50 - 15 = 55 Now we subtract  50, add 15 to both sides:

10x + 50 - 50 - 15 + 15 = 55 - 50 + 15    

10x =  20

x = 2.

8 0
3 years ago
In a class of 40 students, the number of girls is 10 more than the number of boys. We have to find the number of girls and the n
Nadusha1986 [10]

Answer:

b=15 g=25

Step-by-step explanation:

lets translate that story problem to mathematics equations

the problem told that no. of girls are 10 more than no of boys so this will =

g=b+10

then in class there are 40 students that means

g+b=40

now we have to equations with two variables then we should substitute

(b+10)+b=40

lets remove the brackets

2b+10=40 subtract 10 from both sides

2b=30 now divide both by 2

b=15 so g=25 after you write the equation once again with the new proof or number

6 0
3 years ago
(04.05 MC)
nika2105 [10]

Answer:

D

Step-by-step explanation:

Plug in and see.

Check A: Lets plug in (0,3) into y<2/3 x+2.

3<2/3 (0)+2

3<2 is not true so not A

Check C: Lets plug in (3,5) into y<2/3 x+2.

5<2/3 (3)+2

5<2+2

5<4 is not true so not C

Check B: Lets plug in (-3,1) into y<2/3 x+2.

1<2/3 (-3)+2

1<0 is not true so not B

Check D: Lets plug in (1,2) into y<2/3 x+2.

2<2/3 (1)+2

2<2/3+2 is true so D

6 0
3 years ago
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