F(a)=-2a^2 - 5a^4
if a=-3
f(-3)=-2(-3)^2 - 5(-3)^4
=(-2*9) - (5*81)
=-18 - 405
=423
Answer:
x + 2
Step-by-step explanation:
Answer:
I think you have not written the full question
X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6
Answer: Yes
Step-by-step explanation:
