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Brilliant_brown [7]
3 years ago
6

What is this angles measure?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
7 0

Answer:

m<SQR= 11 degrees

m<PQR= 22 degrees

Step-by-step explanation:

Since it is a angle bisector, it bisects the angle <PQR evenly. WE also know that <PQS is 11. From that we know that m<SQR is also 11 degrees since it is congruent to m<PQS and that m<PQR is 11+11 which is 22 degrees.

sukhopar [10]3 years ago
4 0

Answer:

22

Step-by-step explanation:


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4
taurus [48]

Answer:

x^2 - 2x + 10, option B

Step-by-step explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:

i^2 = -1

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

The solutions are:

x_1 = 1 - 3i, x_2 = 1 + 3i

We have to find the polynomial. All option have a = 1. So

(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10

The correct answer is given by option b.

6 0
3 years ago
Consider the function below, which has a relative minimum located at (-3 , -18) and a relative maximum located at (1/3, 14/17).
leonid [27]
First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27).  But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing.  The first derivative of the function is f'(x)=-3x^2-8x+3.  Set the derivative equal to 0 and factor to find the critical numbers. 0=-3x^2-8x+3, so x = -3 and x = 1/3.  We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing.  From there we will look at our points to determine which fall into the "decreasing" category.  Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞.  In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval.  In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval.  In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval.  In order to determine where our points in question fall, look to the x value.  The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12).  The point (-3, -18) is already a min value.
8 0
3 years ago
Write the equation of the line in slope-intercept form using y=mx+b​
natta225 [31]

Answer:

y = 4x + 4

Step-by-step explanation:

Two points you can see on the graph are (0,4) and (-2,-4)

Now, to find the slope, use delta y/ delta x

(-4-4)/(-2-0)

(-8)/(-2) = 4

Slope is 4.

y = 4x + b

Now, to find b, we need the y-intercept, which is the point where x is 0 and the graph crosses the y-axis.

This value is 4. So, the y-intercept is 4

Substitute into your equation

y = 4x + 4

6 0
3 years ago
Read 2 more answers
4x-y=2 <br>what is the solution ​
Rudiy27

Answer= y=-_

Step-by-step explanation:

y= -2+4x

4 0
3 years ago
Consider the functions f(x)=x^2+9x and g(x)= 1/x .
Vikentia [17]

f(g(-1))=-8

g(f(1/2))=4/19

5 0
3 years ago
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