Please may someone help with c

Mathematics

1 answer:

german3 years ago

4 0

Step-by-step explanation:

Distance between two villages = d

$(a) \: \frac{4}{5} \: of \: d = \frac{4}{5} d \\ \\ (b) \: \frac{3}{4} \: of \: d = \frac{3}{4} d \\ \\ (c) \: \frac{4}{5} d - \frac{3}{4} d = 1.5 \\ \\ \therefore \: \bigg(\frac{4}{5} - \frac{3}{4} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{1}{20} \bigg) d = 1.5 \\ \\ \therefore \: d = 1.5 \times 20 \\ \\ \: \: \: \: \: \huge \orange{ \boxed{{ \therefore \: d = 30}}}$

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Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$