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2 years ago

If $1= rs 115.4 ( buying rate ) and $1=rs116.20(selling rate). find the profit while selling and buying $6000.

Mathematics

1 answer:

Galina-37 [17]2 years ago

7 0

The profit is Rs.4800.

<h3>What is profit?</h3>

When, in a transaction, the selling price is greater than the cost price, it means we earn a profit. It is calculated with the help of the formula: Profit = Selling price - Cost price.

Given that,

S.P =$6000

C.P = $6000

If, 1$ = Rs.115.4 (in cost price)

1$ = Rs.116.20 (in selling price)

Then,

C.P = Rs. 115.40×6000

S.P = Rs. 116.20×6000

Then,

Profit = S.P-C.P

= 116.20×6000 -115.40×6000

= (116.20-115.40)×6000

= 0.80×6000

= Rs.4800

Hence, The profit is Rs.4800.

To learn more about profit from the given link:

brainly.com/question/19104371

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Please answer !!!!!!!

Akimi4 [234]

The measure of all the angles is given below:

angle 1= 30

angle 2= 150

angle 3= 30

angle 4= 150

angle 5= 30

angle 6= 150

angle 7= 30

angle 8= 73.5

<h3>What is angle?</h3>

An angle is formed when two straight lines or rays meet at a common endpoint. The common point of contact is called the vertex of an angle.

As,

angle 1= 30 (Vertically opposite angle)

angle 7= 30 (corresponding angle)

angle 4+30= 180 (linear pair)

angle 4= 150

angle 4= angle 2= 150 (Vertically opposite angle)

angle 2= angle 6= 150 (corresponding angle)

angle 1= angle 5= 30 (corresponding angle)

angle (2x+3)= angle 4 (corresponding angle)

2x+3= 150

x= 73.5

Lean more about angle here:

brainly.com/question/13954458

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7 0

1 year ago

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago

im stupid. honestly. just help me pls. this is probably really easy but i aint done any maths in over a month so ion remember ho

KATRIN_1 [288]

Answer:

19 coins

Step-by-step explanation:

We know that mean is the sum of all the elements divided by the number of elements there are: m = t/n, where m is the mean, t is the total sum, and n is the number of elements.

Here, we are given the mean number of coins for all 27 + 18 = 45 children is 16, so m = 16 and n = 45. Then:

m = t/n

16 = t/45

t = 720

This t means that the total number of coins that all the boys and girls have is 720 coins.

Now, we also know the mean number of coins for the boys only, which is 14. Since there are 27 boys, then:

m = t/n

14 = t/27

t = 378

This t means the total number of coins all the boys have.

Subtracting 378 from 720, we get 342, which is the total number of coins the girls have. We also know there are 18 girls, so:

m = t/n

m = 342 / 18 = 19

Thus, the mean is 19 coins.

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