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Ahat [919]
3 years ago
15

Hector is rewriting the expression 7 Superscript 11 in expanded form. How many terms will be multiplied in his rewritten express

ion?
Mathematics
2 answers:
skad [1K]3 years ago
7 0

Answer: 11

Step-by-step explanation:

Im just taking a guess

r-ruslan [8.4K]3 years ago
5 0

Answer:

11 terms.

Step-by-step explanation:

The exponent indicates how many time you will multiply 7 by itself.

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What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
3 years ago
A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
lbvjy [14]

Answer:

2ft

Step-by-step explanation:

5 x 10=50

7 x 12= 84

5+2=7 and 10+2=12

3 0
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If I varies inversely with R and I = 0.25 when R = 18, which equation should be used to show this relationship?
pashok25 [27]
Inverse relationships are of the form xy=k or if you prefer  y=k/x so to find the constant we can say:

18(0.25)=k=4.5

So you could say: IR=4.5 or I=4.5/R
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From: Sam To: You
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Step-by-step explanation:

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