The given parallelogram is a rhombus
Solution:
Option A: Rhombus
Let us recall the property of rhombus.
- Diagonals bisect each other at right angles.
- Opposite angles are congruent.
Here diagonals bisect the angles equally each 72°.
Opposite angles are congruent(72° + 72° = 144°).
Hence the given parallelogram is a rhombus.
Option B: Rectangle
Let us recall the property of rectangle.
- Diagonals bisect each other.
- All the angles of a rectangle are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a rectangle.
Option C: Square
Let us recall the property of square.
- Diagonals bisect each other.
- All the angles of a square are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a square.
Answer:
-4
Step-by-step explanation:
Line segment PQ with points P(-2.5) and Q(-1,1)
m = (y₂ - y₁)/(x₂ - x₁)
m = (1 - 5)/(-1 - (-2)) = -4/1 = -4
Answer:
total=16pens and 10 red pens so ratio=10:16 fraction =5/8
Step-by-step explanation:
