Answer:
For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Step-by-step explanation:
Let the length of the rectangular exercise run = l ft
and width of the run = w ft
Sinoman has to cover a rectangular exercise run from three sides with the fencing material,
So length of the material = (l + 2w) ft
l + 2w = 100
l = 100 - 2w --------(1)
Area of the rectangular area covered = Length × width
A = lw
A = w(100 - 2w) [(l = 100 - 2w)from equation (1)
For maximum area we find the derivative of area and equate it to zero.
![\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdw%7D%3D%5Cfrac%7Bd%7D%7Bdw%7D%5Bw%28100-2w%29%5D)

A' = 100 - 4w
For A' = 0
100 - 4w = 0
4w = 100
w = 25 ft
From equation (1)
l = 100 - 2w
l = 100 - 2×(25)
l = 50 ft
Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Answer:
20 cups
Step-by-step explanation:
divide 9 by .45 and you get 20
Answer:
It has 2 45 degree angles
Step-by-step explanation:
Answer:
angle 2=120°
angle 1=60
Step-by-step explanation:
70+50=120
or
180-(70+50)=60
angles on a straight line add up to 180°
180-60=120
1/6 of an hour= 10 because 60mins=1hour & 60/6=10 so the sailboat travels 2 1/2 miles in 10 mins. So the complex fraction would be 2 &1/2 over 10. Hope it helps!