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jarptica [38.1K]
3 years ago
6

Compare the size of Earth with that of the Sun, the Milky Way galaxy, and the entire universe.

Geography
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

Explained Below in explanation.

Explanation:

Looking at the data in the text, we can see that the diameter of the Sun is about 100 times that of Earth, about 1,500,000 km for the Sun compared to about 12,000 km for Earth. A galaxy such as the Milky Way is about 100,000 light-years in diameter. Since a light-year is about 10¹³ km, this means the Galaxy has a diameter of approximately 10¹⁸ km, or about 10¹⁴ times (100 million million times) the radius of Earth. The most distant objects visible define the limits of the visible universe (which is likely only a small part of the entire universe). These objects are about 10 billion light-years away, or 10²³ km. This is 10¹⁹ times (10 billion billion times) the radius of Earth.

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What is the Wt% of SiO2 in augite?<br><br> (Ca, Fe, Mg, Na)(Mg,Fe,Al) (Si,Al)2 O6
vaieri [72.5K]

Answer:

The weight% of SiO_2 in augite is 13.16 %.

Explanation:

Atomic mass of calcium = 40 g/mol

Atomic mass of iron = 56 g/mol

Atomic mass of magnesium = 24 g/mol

Atomic mass of sodium = 23 g/mol

Atomic mass of aluminum = 27 g/mol

Atomic mass of silicon = 28 g/mol

Atomic mass of oxygen = 16 g/mol

Mass of SiO_2=28 g/mol+ 2\time 16 g/mol=60 g/mol

Molar mass of the augite (Ca, Fe, Mg, Na)(Mg,Fe,Al)(Si,Al)_2 O_6 = M

M=40 g/mol+2\times 56 g/mol+2\times 24 g/mol+23 g/mol+3\times 27 g/mol+2\times 28 g/mol+6\times 16 g/mol=456 g/mol

Weight% of SiO_2 in augite:

w\%=\frac{60 g/mol}{456 g/mol}\times 100=13.16\%

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