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ehidna [41]
2 years ago
14

Write 81.42 as a mixed number

Mathematics
2 answers:
Kruka [31]2 years ago
7 0
81.42 =81 \frac{42}{100}=81\frac{21\times 2}{50\times 2} = \boxed{\bf{81\frac{21}{50}}}
Effectus [21]2 years ago
5 0
81.42
= 81+ 0.42
= 81+ 42/100
= 81+ (42/2) / (100/2)
= 81+ 21/50
= 81 21/50

The final answer is 81 21/50~
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Identify the values of a, b, and c in the following quadratic equation. 3x^2 - 2x + 5 = 0
Kamila [148]
A is always the number with a variable and is squared

B is always the one with a single variable

C is always the lone number or constant

Thus, here are the correct answers:

A = 3x^2
B = -2x
C = 5

Hope this helps!
5 0
3 years ago
Find the surface area of this net.
vagabundo [1.1K]

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6 0
2 years ago
Read 2 more answers
According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio
joja [24]

Answer:

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

p_v =P(t_{44}>2.73)=0.0045    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation    

\bar X=86.7 represent the average life for the sample    

s=8.6 represent the population standard deviation    

n=45 sample size    

\mu_o =83.2 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \leq 83.2  

Alternative hypothesis :\mu > 83.2  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

Give the appropriate conclusion for the test  

First we need to calculate the degrees of freedom given by:

df=n-1=45-1=44

Since is a one side right tailed test the p value would be:    

p_v =P(t_{44}>2.73)=0.0045    

Conclusion    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

8 0
3 years ago
2 Points
Gnesinka [82]
Answers are A, C, and D!
3 0
3 years ago
Please help!!!!!!!!!!
Sunny_sXe [5.5K]

Answer:

From the chapter Playing with numbers

we can define derek has 2×10^2 + 7 × 10^1 + 7× +0^0

as If ABC a number then ABC can be written as 10^2A+10^1B+10^0C

Hope it helps

7 0
2 years ago
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