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larisa [96]
2 years ago
9

To convert 29 metric tons to grams, move the decimal point to the right or left?

Mathematics
2 answers:
mafiozo [28]2 years ago
8 0
I believe to the left, hope that helps
Iteru [2.4K]2 years ago
5 0
You would move the decimal point 6 points to the left. 
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Carly draws quadrilateral JKLM with vertices J(-3,3), K(3,3), L(2,-1),and M(-2, -1). What is the best way to classify the quadri
Trava [24]

Answer:

Trapezoid

Step-by-step explanation:

The points are shown in the attached graph.

<em>You can clearly see from the picture that it is a "Trapezoid".</em>

<em />

<em>Trapezoid</em><em> is basically a quadrilateral (4 sided-figure) that has 1/2 pair of parallel sides.</em>

<em>On the other hand, a </em><em>parallelogram</em><em> has 2 pair of parallel sides.</em>

<em />

Thus, a parallelogram is a special type of trapezoid where there are 2 pair of parallel sides. But trapezoid need not be a parallelogram.

<em>The picture shows 1 pair of parallel sides, hence it is a </em><em>trapezoid.</em>

6 0
3 years ago
Estimate how many 12inches rulers will be about the same length as the flag
MAVERICK [17]
You would need 13/14 12in rulers to make it the size of the flag 
8 0
3 years ago
3.<br>June has 248 oranges. She sells of these oranges. How many oranges did June sell?<br>Answer.​
uranmaximum [27]

Answer:

93. Divide 248 by 8. One eighth of 248 = 31.

June sold 3/8 of the 248 oranges.

If 1/8 = 31 and June sold 3/8 of the oranges.

Multiply 3 × 31. Therefore June sold 93 oranges.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
How is solving inequalities with multiplication and division similar to solving equations with multiplication and division?
bija089 [108]
Because they’re both the opposites of eachothers quantities
5 0
2 years ago
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Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
2 years ago
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