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LiRa [457]
3 years ago
10

5. Cooking oil costs $5.89/kg. How much oil is there if the total cost is $17.92?

Mathematics
1 answer:
Tems11 [23]3 years ago
3 0

Answer: $3.04

Step-by-step explanation:

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Help me with this plase
MakcuM [25]

Answer:

I believe it is A because if you use the slope x it matches with the line.

3 0
2 years ago
In the equation t = 0.7n - 1.3, the dependent variable
Mila [183]

Answer:

The dependent variable is n i think because the hwole problem depends on n

Step-by-step explanation:

3 0
3 years ago
Compare and contrast the rate 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile
Gwar [14]

The values of the rates 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile are equal

<h3>How to compare and contrast the rates?</h3>

The rates are given as:

Rate 1 = 4/5 mile in 8 minutes

Rate 2 = 2/5 mile in 4 minutes

Calculate the above rates

This is done as follows:

Rate 1 = 1/10 mile per minute

Rate 2 =1/10 mile per minute

When the rates are calculated, the values are 1/10 mile per minute

Hence, the values of the rates 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile are equal

Read more about rate at:

brainly.com/question/2021001

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5 0
2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Question 5
polet [3.4K]

Answer:

b, c, e

Step-by-step explanation:

Esoeranza's cat weighs 1.3 x (130% of x). You can select all the expressions that equal to 1.3x.

8 0
3 years ago
Read 2 more answers
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