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2 years ago

13

What fraction is equivalent to 3/9

1 answer:

cluponka [151]2 years ago

7 0

Answer:

There are infinity equivalent fractions to 3/9

Step-by-step explanation:

1 /3, 2 /6, 3/ 9, 4 /12, 5/ 15, 6 /18, 7/ 21, 8/ 24, 9 /27, 10/ 30, 11/ 33, 12/ 36, 13/ 39, 14 /42, 15 /45..........

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BRAINLIEST ANSWER!!!!!

Shkiper50 [21]

Hmm....
I know that the first answer is a coin, but I'm not too sure about the second one.

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3 years ago

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REALLY APPRECIATE YOUR HELP<br><br>Given log x = 3 and log y = 2, prove that x^2 -7xy =3000y

anyanavicka [17]

Answer:

$if \: log(x ) = 3 \\ log_{10}(x) = 3 \\ {10}^{3} = x \\ therfore \to \: \boxed{x = {10}^{3} } \\ \\ if \: log(y ) = 2 \\ log_{10}(y) = 2 \\ {10}^{2} = y \\ therfore \to \: \boxed{y= {10}^{2} }$

Step-by-step explanation:

$x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2} = 3000(10)^{2} + 7( {10}^{3} \times {10}^{2}) \\ {10}^{6} = 3000(10)^{2} + 7( {10}^{3} \times {10}^{2}) \\ {10}^{6} = 3000(10)^{2} + 7( {10}^{5} ) \\ {10}^{6} = 300000 + 700000 \\ \boxed{{10}^{6} = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}$

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3 years ago

Between what two consecutive integers is 152

TEA [102]

Answer:

152 lies between two consecutive integers 151 and 153.

Step-by-step explanation:

Let n be the given integer.

The predecessor of any integer n is given by n-1.

Similarly the successor of an integer n is given by n+1.

For example: Let n be 100

Then its predecessor is 100-1 = 99

Its successor is 100+1 = 101

In the given question, n=152.

Predecessor of 152 = 152 - 1 = 151

Successor of 152 = 152 + 1 = 153

So 152 lies between two successive integers 151 and 153.

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3 years ago

Consider the following cost function.

Makovka662 [10]

Answer:

a)Average cost function = $\bar{C(x)}=\frac{1000+0.1x}{x}$

Marginal cost function = $C'x=0.1$

b) $\bar{C(2000)}=0.6$

$C'(2000)=0.1$

c) $\bar{C(2000)}=0.6$ is the average cost to produce first 2000 items

C'(2000)=0.1 is the marginal cost to produce 2001 th item

Step-by-step explanation:

Cost function: $C(x) = 1000 + 0.1x$

a)Find the average cost and marginal cost functions.

Average cost function = $\bar{C(x)}=\frac{C(x)}{x}$

Average cost function = $\bar{C(x)}=\frac{1000+0.1x}{x}$

Marginal cost function = $C'x=0.1$

b) Determine the average and marginal cost when x = a.

a = 2000

Average cost function = $\bar{C(x)}=\frac{1000+0.1x}{x}=\frac{1000+0.1a}{a}=\frac{1000+0.1(2000)}{2000}=0.6$

So, $\bar{C(2000)}=0.6$

Marginal cost function = $C'(2000)=0.1$

c)Interpret the values obtained in part (b).

$\bar{C(2000)}=0.6$ is the average cost to produce first 2000 items

C'(2000)=0.1 is the marginal cost to produce 2001 th item

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3 years ago

What is the greatest common factor of 15 and 5?

shtirl [24]

Answer:

Step-by-step explanation:

5

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3 years ago

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