Question

The ages of three siblings are all consecutive

Answer 1

Answer:

12 year old is the youngest sibling

Step-by-step explanation:

Given: The ages of three siblings are all consecutive integers.

           The sum of sibling´s age is 39.

Now, finding the age of youngest sibling.

Lets assume the age of youngest sibling be "x"

As given, The ages of three siblings are all consecutive integers.

∴ Age of 2nd sibling will be $(x+1)$

 Age of 3rd sibling will be $(x+2)$

next, forming an equation for the sum of sibling´s age.

⇒$x+(x+1)+(x+2)= 39$

Opening the parenthesis

⇒ $x+x+1+x+2= 39$

⇒$3x+3= 39$

Subtracting both side by 3

⇒$3x= 39-3$

⇒$3x= 36$

Dividing both side by 3

⇒$x= \frac{36}{3}$

∴ x= 12

Subtituting the value of x to find the age of other sibling

∴Youngest sibling age= 12 years

2nd sibling age= 13 years

3rd sibling age= 14 years

Hence, The youngest sibling is 12 years old.