Ask question

Ask question

All categories

3 years ago

13

The energy released by metabolism of 1 average candy bar is 1 x 10^6 joules.

1 answer:

Elis [28]3 years ago

3 0

Answer: 32

Step-by-step explanation:

Given: The energy needed for 1 hour of running for an adult $=4.5\times10^6\ joules.$

Therefore. the energy needed for seven hours of running= $=7\times4.5\times10^6\ joules.=31.5\times10^6\ joules$

Since, he energy released by metabolism of 1 average candy bar $=1\times10^6\ joules.$

Therefore, the number of candy bars an adult need to eat to supply the energy needed for seven hours of running.= $\frac{31.5\times10^6}{1\times10^6}=31.5\approx32$

Hence, the adult need to eat 32 candies to supply the energy needed for seven hours of running.

You might be interested in

Forensic specialists can estimate the height of a deceased person from the lengths of the person's bones. These lengths are subs

Lera25 [3.4K]

Answer:

$130.2845\leq h\leq 137.7245$

Step-by-step explanation:

Given an inequality that relates the height h, in centimeters, of an adult female and the length f, in centimeters, of her femur by the equation

$|h - (2.47f + 54.10)| \leq 3.72$

If an adult female measures her femur as 32.25 centimeters, we can determine the possible range of her height by plugging f = 32.25cm into the modelled equation as shown:

$|h - (2.47(32.25) + 54.10)| \leq 3.72\\|h - (79.9045 + 54.10)| \leq 3.72\\|h - (134.0045)| \leq 3.72\\$

If the modulus function is positive then:

$h - 134.0045 \leq 3.72\\h \leq 3.71+134.0045\\h\leq 137.7245$

If the modulus function is negative then:

$-(h - 134.0045) \leq 3.72\\-h+134.0045 \leq 3.72\\-h\leq 3.72-134.0045\\-h\leq -130.2845\\$

multiply through by -1

$-(-h)\geq -(-130.2845)\\h\geq 130.2845\\130.2845\leq h$

combining the resulting inequalities, the estimate of the possible range of heights will be $130.2845\leq h\leq 137.7245$

8 0

3 years ago

Ax + 4y = 5z, for a

Stolb23 [73]

Answer:A=5z-4y/x

Step-by-step explanation:

You must bring 4y over first making it negative then to separate the x from the A you have to divide

4 0

3 years ago

Read 2 more answers

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

<u>Step 1</u>:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

<u>step 2:-</u>

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

<u>verification:-</u>

<u></u> $AC^2 = AB^2 + BC^2$ <u></u>

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

4 years ago

Read 2 more answers

Hello what is the answer please 5+30÷10=

Brilliant_brown [7]

Answer:

Mizuki is here to help! The answer is 8!

Step-by-step explanation:

5 + 30 ÷ 10 =

5 + 3 =

8

Remember PEMDAS!

8 0

3 years ago

Read 2 more answers

GIVING BRAINLESS HELP!!

aliina [53]

Jessica bought 2.25 yards more material than Derek. Hope this helped!

4 0

3 years ago