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HACTEHA [7]
3 years ago
6

If you vertically compress the absolute value parent function, f(x) = [ 41, by a

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

g(x) = \frac{1}{5}  |x|

Step-by-step explanation:

Given

f(x) = |x|

<em>Vertically compressed</em>

Compression Factor = 5

Required

Find the equation of the new function;

Let the new function be represented by g(x)

Let c represented the compression factor;

such that c = 5

When a function f(x) is vertically compressed by factor c, the new function becomes

f(\frac{1}{c}x)

From properties of functions;

f(\frac{1}{c}x) = \frac{1}{c} *f(x)

This implies that

g(x) = f(\frac{1}{c}x) = \frac{1}{c} *f(x)

g(x) = \frac{1}{c} *f(x)

Recall that f(x) = |x| and c = 5

g(x) = \frac{1}{5} * |x|

g(x) = \frac{1}{5}  |x|

<em>Hence, the new function is </em>g(x) = \frac{1}{5}  |x|<em />

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What annual rate of interest would you have to earn on an investment of $3500 to ensure receiving $273.00 interest after 1 year?
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To find the answer, we will have to find the percentage of $273 to $ 3500, and we can use the formula:

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4 years ago
Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
4 years ago
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