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2 years ago

Find a point-slope form for the line with slope 1/5 and passing through the point (-4,-9).

Mathematics

1 answer:

sattari [20]2 years ago

3 0

Answer:

y + 9 = $\frac{1}{5}$ (x + 4)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = $\frac{1}{5}$ and (a, b) = (- 4, - 9) , thus

y - (- 9) = $\frac{1}{5}$ (x - (- 4) ) , that is

y + 9 = $\frac{1}{5}$ (x + 4)

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2 years ago

What is the x-value of the solution of the system of

LenaWriter [7]

Answer:

Step-by-step explanation:

hello :

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3 years ago

Read 2 more answers

7. What is the slope of the line that passes through (12, 10) and (11, 15)?

amid [387]

Answer:

-5

Step-by-step explanation:

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3 years ago

the position of a deep sea probe is -2 3/4 fathoms relative to the sea level. after finishing taking data, it moves to -2 5/8 fa

alisha [4.7K]

Answer:

The first mission

Step-by-step explanation:

The depth readings are

The first mission: - 2 3/4 fathoms
The second mission: - 2 5/8 fathoms

Comparing the readings

- 2 3/4 = - 2 6/8 and - 2 5/8

Absolute values compared

2 6/8 > 2 5/8

Indicating the greater value on the first mission

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8 0

3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago