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drek231 [11]
3 years ago
9

4^6 X 4^3 4^9 4^18 12^9 64^9

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0

Answer:

4^9

Step-by-step explanation:

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3/5 as a decimal is 0.6

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What is the estimate of 15 ÷ 485
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i think it 30 but I could be wrong

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I need help with this go to the screenshot below plz
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the correct answer is 4

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Twice the difference of a number and 9 is equal to three times the sum of the number and 6. Find the number
bezimeni [28]

After modelling the mathematical statement and solving its equivalent mathematical relation, we get x = -36.

<h3>What is Equation Modelling?</h3>

Equation modelling is the process of writing a given mathematical statement in the form of a numeric mathematical expression taking into considerations the operations, constants and other variables.

Given in the question is a number such that twice the difference of a number and 9 is equal to three times the sum of the number and 6.

Assume that the number is x. Now, we will model the equation and solve for x. According to the question, the following mathematical relation represents the statement-

2(x - 9) = 3(x + 6)

2x - 18 = 3x + 18

x = - 36

Therefore, the number is -36.

To solve more questions on Equation modelling, visit the link below-

brainly.com/question/13536824

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8 0
11 months ago
Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

-3x + 3 = 0

x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
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